DestructoMutt wrote:can someone check my math?
1 kilowatt vaporizes 1.5 g/mol of either water or ethanol (or a combination of the two) every minute.
molar mass of ethanol is 46.07 g/mol, density is 0.789 g/cc at STP (yes, it drops as temperature climbs)
molar mass of water is 18.0 g/mol, density is 1.0 g/cc at STP (yes, it drops as temperature climbs)
for ethanol then: 1.5 g/mol x 46.07 g/mol = 69.1 g/mol / 45 liters => 1.5 g = 1 liter of vapor, or 1.95cc = 1 liter of vapor.
for water: 18.0 g/mol x 1.5 g/mol = 27 g/mol; 27 g/mol / 45 l/min => 0.6g = 1 liter of vapor, or 1 liter of vapor equals 0.6 cc of water.
obviously it's going to be less at temperatures greater than STP, but this somewhat close (water drops to 0.96 at 93C).
Zymurgy Bob wrote:What do we do with those numbers?
DestructoMutt wrote:1.95cc (of liquid ethanol) = 1 liter of (ethanol) vapor.
DestructoMutt wrote:1 liter of (water) vapor equals 0.6 cc of (liquid) water.
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